You are here: Home > Silver Bank > Free useful guideline for silver presents

Dr Dave P December 29, 2010 at 4:25 am

A) Hg2+2 Present. Hg2Cl2 partially soluble in hot water 0.001g/100ml. Hg2Cl2 forms black ppt when react with concentrated ammonia (Hg metal). Ag+ , Pb+2 absent. B) Ag+ Present. AgCl forms soluble Ag(NH3)2+. AgCl insoluble in hot H2O, Pb+2, Hg2+2 absent.C) Pb+2 Present. PbCl2 is partially soluble in hot water 3g/100 ml. Ag+ and Hg2+2 absent.ref: http://72.14.253.104/search?q=cache:YbHN7-fSYSAJ:employees.oneonta.edu/kotzjc/LAB/SilverGroup.pdf+silver+group+tests&hl=en&ct=clnk&cd=4&gl=us

cstspeedy December 29, 2010 at 4:35 pm

b) Electrical current must be applied to the iron fork

Teehee <3 December 30, 2010 at 3:45 am

I’d probably wear it to some party or something, and i’d wear it with an plain white cami or tank top & black or pale blue skinny jeans with flats or if you find it a bit cold–try ankle boots I’d also pair it with an long pearl necklace or something similar just to add a classy touch.goodluck (:

Amy December 30, 2010 at 3:50 pm

How about here? http://www.etsy.com/listing/31656502/custom-silver-guitar-pick-necklace

martinthurn December 31, 2010 at 3:53 am

Hasbro wants to make more money by selling more toys. Star Wars collectors want to have every possible toy; gold and silver versions are two different toys; Hasbro sells more.You’ll also notice the gold one says “Ultimate Galactic Hunt”. The gold ones are more limited in number than the silver ones. Search ebay for “UGH Chewbacca” and kick youself for not buying it

Arnaq December 31, 2010 at 4:14 pm

well the acid is simply added to know if sulphite ion or carbonate ion is present…usually when acid are added, required observations are to look for effervescence

SkyWolf January 1, 2011 at 4:26 am

Sterling silver is classy without being overly wasteful- a way to give a gift of value without breaking your bank. I got my partner a sterling ring for our engagement- in fact, some girls prefer sterling because it’s not so expensive or overly flashy.

Trinity January 1, 2011 at 4:05 pm

By getting illegal books (audio or written) you are only contributing to a dwindling book market and making sure that the author does not get full credit for his works. In addition, you make it harder for aspiring authors too get published.Go to the library: cheap, legal, and convenient.

Boris Von Snuggles January 2, 2011 at 4:26 am

Joy of opening is: Oh my god, oh my god, oh my god!

Masasune January 2, 2011 at 4:28 pm

I have to make 2 assumptions:1. They react on a 1 to 1 ratio2. By 3.80 and 5.43 you mean 3.80 mol and 5.43 mol respectively.Your limiting reactant in this case is the sodium carbonate, so you have all of it being used up. Because of this you are left with some silver nitrate left:5.43mol – 3.80mol = 1.63 mol Silver Nitrate left over.Using the molecular weight you can convert this to mass:1.63 mol * 169.88 g/mol = 276.9 g Silver Nitrate left over

Dr.A January 3, 2011 at 3:57 am

Na2CO3 + 2 AgNO3 = Ag2CO3 + 2 NaNO3moles Na2CO3 = 5.00 g/105.9884 g/mol=0.0472moles AgNO3 = 5.00 g/ 169.87 g/mol= 0.0294 (limiting reactant)moles Ag2CO3 = 0.0294/2=0.0147mass Ag2CO3 = 0.0147 mol x 275.75 g/mol=4.06 gmoles NaNO3 = 0.0294mass NaNO3 = 0.0294 x 84.9935 g/mol= 2.50 gmoles Na2CO3 needed = 0.0294/2=0.0147moles Na2CO3 in exess = 0.0472 – 0.0147 =0.0325mass Na2CO3 in excess = 0.0325 x 106.9884 =3.48 gsilver nitrate =0check : mass products = 5.00 + 5.00 = 10.00mass products = 2.50 + 4.06 =6.56 gmass reactant in excess = 3.483.48 + 6.56 = 10 g

Jennifer Johnson January 3, 2011 at 4:17 pm

I will commend Tiffany for you,it is a luxurious brand with good quality and whopping price.On sale up to 70% OFF on the site:http://www.discountmuch.com/?=mwn

DaRk ChOcOlAtE Class of 2010! January 4, 2011 at 4:20 am

Letoya Luckett.

volcanic_jaguar January 4, 2011 at 4:01 pm

A limiting reactant problem. Convert each of the masses of the reactants to g of silver carbonate. The smaller result tells you which reactant runs out first. That is the answer. I got 3.71g.

Captain Matticus, LandPiratesInc January 5, 2011 at 3:50 am

33.24 * (1 – .925) = 2.493 gThere are 2.493 grams of Copper in the alloy. The mass of 1 mole of Copper atoms is 63.546 g2.493 / 63.546 = 0.039231422906241148144651118874516 moles1 mole contains 6.02 * 10^23 atoms:23 617 316 589 557 171 183 080 atomsor2. 361 731 658 955 717 118 308 x 10^15 atoms